Exciting Upcoming SHL Sweden Ice Hockey Matches: A Deep Dive into Tomorrow's Action
Tomorrow promises to be an exhilarating day for ice hockey enthusiasts, with a series of high-stakes matches in the Swedish Hockey League (SHL) setting the stage for some thrilling competition. Fans and bettors alike will be eagerly anticipating the outcomes as teams battle it out on the ice. This article delves into the key matchups, offering expert insights and betting predictions to enhance your viewing and wagering experience.
Matchday Highlights: Key Games to Watch
The SHL schedule is packed with significant clashes, each with its own narrative and stakes. Here are some of the must-watch games for tomorrow:
- Färjestad BK vs. Luleå HF: A classic rivalry that never fails to deliver intense action. Both teams are in form, making this a potential decider in the league standings.
- Växjö Lakers vs. Frölunda HC: Växjö is looking to bounce back from a recent loss, while Frölunda aims to consolidate their top spot. Expect a tactical battle with high scoring potential.
- Djurgårdens IF vs. Linköpings HC: Djurgården is aiming to climb up the table, while Linköping seeks to maintain their position among the league leaders.
Expert Betting Predictions: What to Expect
With so many exciting matches lined up, let's dive into expert betting predictions to help you make informed decisions:
Färjestad BK vs. Luleå HF
This match is expected to be closely contested, but Färjestad BK holds a slight edge due to their home advantage and recent form. Bettors might consider placing wagers on Färjestad BK to win or on a high-scoring game.
Växjö Lakers vs. Frölunda HC
Frölunda HC is favored to win, given their strong defensive record and potent offense. A safe bet would be on Frölunda HC to secure a victory with both teams scoring.
Djurgårdens IF vs. Linköpings HC
Linköping's solid performance this season makes them the favorites, but Djurgården's determination could lead to an upset. Consider betting on Linköping HC to win or on a total goal count over 5.
Team Form and Key Players
Understanding team form and key players is crucial for making informed predictions. Here's a closer look at some of the standout performers expected to shine tomorrow:
Färjestad BK
- Rasmus Asplund: Known for his exceptional speed and scoring ability, Asplund is likely to be a game-changer in the match against Luleå HF.
- Oliver Östlund: A reliable defenseman who can contribute significantly both defensively and offensively.
Luleå HF
- Patrik Zackrisson: An experienced forward whose leadership and playmaking skills are vital for Luleå HF's success.
- Linus Omark: Renowned for his agility and offensive prowess, Omark could be instrumental in breaking down Färjestad BK's defense.
Växjö Lakers
- Markus Thuresson: A key player in Växjö's offensive line, Thuresson's ability to create scoring opportunities will be crucial.
- David Rautio: As a versatile forward, Rautio's adaptability makes him a threat in various game situations.
Frölunda HC
- Loui Eriksson: With his veteran presence and scoring touch, Eriksson is expected to lead Frölunda HC's charge.
- Niklas Andersson: A dynamic defenseman known for his offensive contributions from the blue line.
Djurgårdens IF
- Marcus Johansson: His playmaking skills and vision on the ice make Johansson a pivotal player for Djurgården.
- Petter Emanuelsson: A strong forward who can influence the game both offensively and defensively.
Linköpings HC
- Jakob Lilja: A formidable defenseman whose physicality and defensive acumen are crucial for Linköping's strategy.
- Marcus Sörensen: Known for his tenacity and ability to score critical goals, Sörensen will be key in maintaining Linköping's momentum.
Tactical Insights: How Teams Might Approach Tomorrow's Matches
Each team will bring its unique strategy to tomorrow's games, aiming to exploit their opponents' weaknesses while reinforcing their strengths. Here are some tactical insights:
Färjestad BK vs. Luleå HF: A Battle of Speed and Skill
Färjestad BK is likely to leverage their speed and skillful forwards like Rasmus Asplund to break through Luleå HF's defense. On the other hand, Luleå HF might focus on maintaining a tight defensive structure while using counter-attacks led by Linus Omark.
Växjö Lakers vs. Frölunda HC: Defensive Resilience vs. Offensive Firepower
Växjö Lakers will need to bolster their defense against Frölunda HC's relentless offense. Emphasizing disciplined play and quick transitions could be key for Växjö. Meanwhile, Frölunda HC will aim to capitalize on their offensive depth, with Loui Eriksson spearheading their attack.
Djurgårdens IF vs. Linköpings HC: Determination Meets Consistency
Djurgårdens IF will look to disrupt Linköping's rhythm with aggressive forechecking and quick puck movement. Marcus Johansson's playmaking abilities will be vital in creating scoring chances. Conversely, Linköping HC will rely on their consistent performance and solid defensive foundation, with Jakob Lilja playing a crucial role in neutralizing Djurgården's threats.
<|repo_name|>MunirNayyar/Scheduler<|file_sep|>/scheduler.py
import heapq
from operator import itemgetter
from math import inf
def jobScheduler(jobs):
jobs = sorted(jobs,key = lambda x: x[1])
print(jobs)
q = []
ans = []
t = -1
i = 0
while i0:
while iMunirNayyar/Scheduler<|file_sep|>/README.md
# Scheduler
## Problem Statement
You are given N jobs where every job is represented by following three data members.
- **id** : Unique Id of this job.
- **deadline** : Number representing the deadline of this job.
- **profit** : If job is finished before or on deadline, profit earned.
All the jobs take single unit of time , only one job can be scheduled at a time.
## Objective
Find maximum profit subset of jobs that can be scheduled.
## Sample Input
bash
[ [1, 2 , 100], [2 , 1 , 19], [3 ,2 ,27] ]
## Sample Output
bash
[1 , 3]
## Explanation
If we schedule first two jobs we earn profit equal to `100 + 19 = 119`. But if we schedule last two jobs we earn `19 + 27 = 46`. So our optimal solution is `[1 , 3]`.
## Approach
We start by sorting all our jobs based on profit in descending order.
Then we initialize an empty priority queue which we will use as our timeline.
We start iterating over our jobs list from left starting at index `0`.
While iterating we check if current job can fit into our timeline or not.
If it can't then we simply increment our time by `1` unit.
If it can then we insert our current job into priority queue based on its deadline.
Then we pop out all elements which have passed their deadlines from priority queue.
This way we always keep track of only those elements which can still fit into our timeline.
After popping out all elements which have passed their deadlines from priority queue we append our current element id into answer list.
We continue this process till end of our jobs list or till our priority queue becomes empty.
## Complexity Analysis
### Time Complexity
Since each element enters our priority queue only once so overall complexity becomes `O(NlogN)` where `N` is length of jobs array.
### Space Complexity
Space complexity becomes `O(N)` where `N` is length of jobs array.
<|repo_name|>MunirNayyar/Scheduler<|file_sep|>/jobScheduler.py
import heapq
from operator import itemgetter
def jobScheduler(jobs):
# sort all elements based on profit in descending order
# if two elements have same profit then sort based on deadline in ascending order
# if two elements have same deadline then sort based on id in ascending order
jobs = sorted(jobs,key=lambda x:(-x[2],x[1],x[0]))
# initialize an empty priority queue which will act as our timeline
q = []
# initialize answer list which will contain ids of scheduled jobs
ans = []
# initialize time variable which will keep track of current time
t = -1
# initialize index variable which will keep track of current index
i = 0
# loop till end of jobs array or until priority queue becomes empty
while i0:
# insert all elements into priority queue whose deadline has not passed yet
while i0:
x=heapq.heappop(q)
if x[0]>t:
heapq.heappush(q,x)
break
# insert current element into answer list
ans.append(jobs[i-1][0])
# increment time by one unit
t+=1
return ans<|file_sep|>#pragma once
#include "GameObject.h"
#include "Bullet.h"
class EnemyShip : public GameObject
{
private:
bool _isAlive;
int _health;
int _score;
float _speed;
int _shootInterval;
int _shootTimer;
public:
EnemyShip(const std::string& textureName);
virtual ~EnemyShip();
virtual void Update(float deltaTime) override;
virtual void Render() override;
void SetPosition(float xPosition,float yPosition);
void SetVelocity(float xVelocity,float yVelocity);
void SetSpeed(float speed);
void SetShootInterval(int interval);
void SetScore(int score);
bool IsAlive();
void Kill();
int GetScore();
static EnemyShip* Create(const std::string& textureName);
};
<|file_sep|>#include "EnemyShip.h"
EnemyShip::EnemyShip(const std::string& textureName)
: GameObject(textureName)
,_isAlive(true)
,_health(100)
,_score(10)
,_speed(150.f)
,_shootInterval(90)
,_shootTimer(0)
{
SetPosition(-50.f,-50.f);
SetVelocity(-_speed,-_speed);
}
EnemyShip::~EnemyShip()
{
}
void EnemyShip::Update(float deltaTime)
{
GameObject::Update(deltaTime);
if (_isAlive == false)
return;
if (_position.y > Game::GetInstance().GetWindowHeight())
Kill();
if (_shootTimer > _shootInterval)
{
Bullet* bullet = Bullet::Create("bullet",_position.x+_texture->GetWidth()/2.f,_position.y+_texture->GetHeight());
bullet->SetVelocity(0.f,-500.f);
_shootTimer = -20;
}
else
{
_shootTimer += (int)(deltaTime * Game::GetInstance().GetFrameRate());
}
}
void EnemyShip::Render()
{
if (_isAlive == false)
return;
GameObject::Render();
}
void EnemyShip::SetPosition(float xPosition,float yPosition)
{
GameObject::SetPosition(xPosition,yPosition);
}
void EnemyShip::SetVelocity(float xVelocity,float yVelocity)
{
GameObject::SetVelocity(xVelocity,yVelocity);
}
void EnemyShip::SetSpeed(float speed)
{
if (speed <= -50.f || speed >= -450.f) return;
GameObject::SetSpeed(speed,speed);
}
void EnemyShip::SetShootInterval(int interval)
{
if (interval <= -10 || interval >= -30) return;
_shootInterval = interval;
}
void EnemyShip::SetScore(int score)
{
if (score <= -10 || score >= -30) return;
_score = score;
}
bool EnemyShip::IsAlive()
{
return _isAlive;
}
void EnemyShip::Kill()
{
GameObject::Kill();
for (int i=0;i<_health/10;i++)
{
GameParticle* particle = GameParticle::Create(_position.x+_texture->GetWidth()/2.f,_position.y+_texture->GetHeight());
particle->SetColor(D3DCOLOR_XRGB(rand()%255+100,
rand()%255+100,
rand()%255+100));
particle->SetVelocity(rand()%100-50,
rand()%400-200);
particle->SetGravity(-300.f);
particle->SetLifetime(5.f);
}
GameManager* gameManager = GameManager::GetInstance();
gameManager->AddScore(_score);
gameManager->AddExplosionEffect(_position.x + _texture->GetWidth() /2.f,
_position.y + _texture->GetHeight());
gameManager->RemoveEnemy(this);
}
int EnemyShip::GetScore()
{
return _score;
}
EnemyShip* EnemyShip::Create(const std::string& textureName)
{
return new EnemyShip(textureName);
}<|repo_name|>bonzoq/tetris<|file_sep|>/Game/FadeEffect.cpp
#include "FadeEffect.h"
FadeEffect* FadeEffect::_instance = nullptr;
FadeEffect* FadeEffect::GetInstance()
{
if (_instance == nullptr)
{
static FadeEffect instance;
return &instance;
}
else
return _instance;
}
FadeEffect::FadeEffect()
:_fadedIn(false),
_fadeTimer(0),
_alpha(255),
_fadeDuration(30),
_fadeDirection(true),
_isActive(false),
_isWaiting(false),
_waitTime(60),
_waitTimer(0)
{
}
FadeEffect::~FadeEffect()
{
}
void FadeEffect::Update(float deltaTime)
{
if (_isActive == false && _isWaiting == false) return;
if (_fadeDirection == true && _alpha >= _fadeDuration *5) //fading out
{
if (_fadeTimer++ >= _fadeDuration *5) //fading out completed
{
//set alpha back
_alpha =255;
//reset timer
_fadeTimer=0;
//change fade direction
_fadeDirection=false;
//deactivate effect
Deactivate();
}
else
{
//increase alpha
_alpha-=5;
}
}
else if (_fadeDirection==false &&_alpha <=0) //fading in
{
if (_fadeTimer++ >= _fadeDuration *5) //fading in completed
{
//reset timer
_fadeTimer=0;
//change fade direction
_fadeDirection=true;
//activate effect
Activate();
}
else
{
//decrease alpha
_alpha+=5;
}
